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sEC^6(x)的不定积分怎么做?

令x³=tanu ∫[x²/√(1+x⁶)]dx =⅓∫[1/√(1+x⁶)]d(x³) =⅓∫[1/√(1+tan²u)]d(tanu) =⅓∫[sec²u/secudu =⅓∫secudu =⅓ln|secu+tanu| +C =⅓ln|√(1+x⁶)+x³| +C

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