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mysql怎么查询某一字段不同值,在该字段中出现的次数

SELECT num, COUNT(num) AS `count` FROM ( SELECT num FROM aaa UNION ALL SELECT num FROM bbb UNION ALL SELECT num FROM ccc ) AS Temp GROUP BY numORDER BY num

select distinct 品牌 from 表名 或者 select 品牌 from 表名 group by 品牌

加个count就可以了,语句如下 select count(distinct age) from table

以时间为跨度统计不同的值,在该时间出现的次数。 语言如下: select count(*),'列名' from tablename group by '列名' select count(*),a_yqm from user group by a_yqm 举例: 这里,我要查询出1年内每个月份periods字段不同值的次数。比如下...

select distinct 品牌 from 表名 或者 select 品牌 from 表名 group by 品牌

SELECT city_name, title, COUNT(*) FROM tuan_info GROUP BY city_name, title HAVING COUNT(*) >1

下面以 sqlserver数据库为例进行说明。 select * from TableA where b in (select b from TableA group by b having count(b) > 1) 这样就列举出了b字段所有的重复数据,可以根据对应的行号,取得位于第几行。 如果要查询a字段或者c字段重复数据...

select 用户id from 表名 where 评分=2 group by 用户id having count(评分)>=2unionselect 用户id from 表名 where 评分=4 group by 用户id having count(评分)>=1

MySQL中的SQL语句可以这样写: SELECT *FROM newtableWHERE newimage1 = 'xxx' OR newimage2 = 'xxx' OR newimage3 = 'xxx'; Java代码: rs=st.executeQuery("SELECT * FROM newtable WHERE newimage1 = '" + newsid + "' OR newimage2 = '" + n...

$total=0; //预设变量,用于存放累加结果 $sql="查询语句"; $sql=mysql_query($sql); while($as=mysql_fetch_array($sql)){ $total=$total+$as[0]; } 还有一种办法更好,假如你要累加的字段名为 price, 则: $sql="select sum(price) as total f...

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