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mysql怎么查询某一字段不同值,在该字段中出现的次数

select distinct 品牌 from 表名 或者 select 品牌 from 表名 group by 品牌

SELECT num, COUNT(num) AS `count` FROM ( SELECT num FROM aaa UNION ALL SELECT num FROM bbb UNION ALL SELECT num FROM ccc ) AS Temp GROUP BY numORDER BY num

select s.`b`, count(*) c from `table` as s group by s.`b`

select 字段名, count(*) from 表 group by 字段名

in(v1,v2..vn) ,符合v1,v2,,,vn才能被查出 IN关键字可以判断某个字段的值是否在指定的集合中。如果字段的值在集合中,则满足查询条件,该纪录将被查询出来。如果不在集合中,则不满足查询条件。其语法规则如下:[ NOT ] IN ( 元素1, 元素2, …, ...

加个count就可以了,语句如下 select count(distinct age) from table

查看可用如下方法: 1、创建测试表,插入数据: create table product(id int,name varchar(10),totol int)insert into product values (1,'香蕉',100)insert into product values (2,'橘子',67)insert into product values (3,'葡萄',89)insert...

表结构呢? select * from tab where 商品编码 IN ( SELECT 商品编码 FROM tab GROUP BY 商品编码 HAVING COUNT(*) > 1)

select count(distinct(name)) from xx

SELECT COUNT(0) FROM article WHERE title='《测试文章》';

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