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mysql怎么查询某一字段不同值,在该字段中出现的次数

select s.`b`, count(*) c from `table` as s group by s.`b`

你的记录集里只有2条呀,除了李四,或者也可以这样写 select * from t_user where name not in ('李四'); 这样也可以查除了name是李四的总条数 select COUNT(*) from t_user where name not in ('李四');

加个count就可以了,语句如下 select count(distinct age) from table

select count(distinct(name)) from xx

SELECT num, COUNT(num) AS `count` FROM ( SELECT num FROM aaa UNION ALL SELECT num FROM bbb UNION ALL SELECT num FROM ccc ) AS Temp GROUP BY numORDER BY num

SELECT city_name, title, COUNT(*) FROM tuan_info GROUP BY city_name, title HAVING COUNT(*) >1

select distinct 品牌 from 表名 或者 select 品牌 from 表名 group by 品牌

SELECT type, count(1) AS counts FROM material GROUP BY type。这是统计material表中type的重复次数

需要用group by中的having子句。 1、如test表中有如下数据: 2、现要查出dept出现2次以上的dept。可用如下语句: select dept from test group by dept having count(*) >2;3、查询结果:

select `字段A`,count('字段A') as `字段B` from tableName group by `字段A`

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