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2,2,11,11,4个数怎样算24点

[﹙2÷11﹚+2]×11=24

你好!用2,2,11,11算24点,共有4种算法。 [﹙2÷11﹚+2]×11 [2+﹙2÷11﹚]×11 11×[﹙2÷11﹚+2] 11×[2+﹙2÷11﹚]

每个数只能用一次吗?

(2+(2/11))*11=24

1: (2 + 2 ÷ 11) × 11 2: (2 + (2 ÷ 11)) × 11 3: (2 ÷ 11 + 2) × 11 4: ((2 ÷ 11) + 2) × 11 5: 11 × (2 + 2 ÷ 11) 6: 11 × (2 + (2 ÷ 11)) 7: 11 × (2 ÷ 11 + 2) 8: 11 × ((2 ÷ 11) + 2)

3*(10+2)-12 =3*12-12 =36-12 =24; 3*(10*2-12) =3*(20-12) =3*8 =24; 3*10-12/2 =30-6 =24; 3*12-10-2 =36-10-2 =24; 10/(3+2)*12 =10/5*12 =2*12 =24; (10*2-12)*3 =(20-12)*3 =8*3 =24; 10*2+12/3 =20+4 =24; …… 供参考。

共有48种解法,下面是其中的8种: 更多解法只要移动1的位置或/和把1×或×1中乘号改成除号就能得到 (1)11×2+2×1=24 (2)2×11+2×1=24 (3)11×2+1×2=24 (4)2×11+1×2=24 (5)1×2+11×2=24 (6)2×1+11×2=24 (7)1×2+2×11=24 (8)2×1+2×11=24

你好,你的这4个数字是不能列式计算得24的,所以此题无解,请采纳!

只用加减乘除无法算得24,如果用根号则可,如: 2-根号4+11+13=24

1: (2 + 2 ÷ 11) × 11 2: (2 + (2 ÷ 11)) × 11 3: (2 ÷ 11 + 2) × 11 4: ((2 ÷ 11) + 2) × 11 5: 11 × (2 + 2 ÷ 11) 6: 11 × (2 + (2 ÷ 11)) 7: 11 × (2 ÷ 11 + 2) 8: 11 × ((2 ÷ 11) + 2)

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