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1X99+99x99

1X99+99x99 =99×(1+99) =99×100 =9900

99+1×99 =99+99 =(100-1)+(100-1) =100+100-1-1 =200-

99+99x99 =99x(1+99) =99x100 =9900

199X99十199 =199×(99+1) =199×100 =19900 希望

99x(1001)x99 =99x99x99 =(100-1)(100-1)(100-1)

=99x(100-1)+1 =9900-99+1 =9900-98 =9802

62*99+99*99 =62*(100-1)+99*(100-1) =6200-62+9900

99*99+99 =99*99+99*1 =99(99+1) =99*100 =9900

1/2x2/3x3/4x…x98/99x99/100的过程:前一个分数的分母与后一个分数的分子约分抵

=(2分之1+2分之1)×99 =1×99 =99 你好,本题已解答,如果满意,请点右上角“采纳答案

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