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10sin(3/2兀)等于

sin(3/2*π)=sin(π+1/2)=-sin(1/2π)=-1 那么10sin(3/2*π

sin2πt最小正周期为 2π/2π=1 sin3πt最小正周期为 3π/2π=3/2 f(

∵-3兀/2 在负半轴 ∴-3兀/2+a在第四象限 ∴sin(a-3兀/2)<0 ∴si

答: sin(2π/3-C)+sinC=√3 sin2π/3cosC-cos2π/3sinC+s

 sin(a-2π/3)=-sin(π/2+π/6-a)=-cos(π/6-a)=

f(x)=√3sin2wx+1(w>0)在区间[-3π/2,π/2]上为增函数, u=2wx

5sin2πt+10sin3πt = 10sinπtcosπt+10[3sinπt-4(sinπt

这个是高中的知识,用到的三角函数的诱导公式。 y1+y2 =20sin(wt+π/3)+10si

sin(θ+π4)= 3√1010 sin(2θ-π3)=sin(2(θ+π4)-5π6

1. 3cos2α=sin(π/4-α) ==> 3(cosα+sinα)(cosα-

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