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用jAvA编写程序求n!

import java.util.Scanner; public class A{ //下面的方法是对单个数求阶乘,并返回 public static int jieCheng(int n){ int sum=1; for(int i=1;i

import java.util.Scanner;public class Text{ public static void main(String args[]){ System.out.println("请输入n"); Scanner sc = new Scanner(System.in); int n= sc.nextInt(); int t=1; int i=1; while(i

import java.util.Scanner; //递归法求阶乘,eclipse编译通过 public class Test { public static void main(String srag[]){ int num = 0; while(true){ System.out.println("请输入一个正整数:"); Scanner sc = new Scanner(System.in); num = ...

1:看题目分析,偶数是负的,奇数是正的,那么第一反应就是奇偶数的筛选 2:实现:使用求余运算符“%” 3:代码实现: package com.fuzhu.test;public class TestCase { public static void main(String[] args) { new TestCase().test(12); } /** ...

import java.util.Scanner; public class Test { public static void main(String[] args) { Scanner cin = new Scanner(System.in); int n = cin.nextInt(); int result = 1; for (int i = 1; i

Scanner s = new Scanner(System.in);//通过new Scanner(System.in)创建一个Scanner,控制台会一直等待输入int a = s.nextInt();//调用Scanner的nextInt()方法获取输入的整数System.out.println(a*a);//输出这个数的平方

Java程序: import java.util.Scanner; public class Test25 { public static void main(String[] args) { Scanner scan = new Scanner(System.in); int i, n; long f, sum; System.out.print("n : "); n = scan.nextInt(); f = 1; sum = 0; for...

import java.util.Scanner; /* * 用java编写程序计算x的n次幂 * */ public class Test40003 { public static void main(String[] args) { int repeat;//定义要幂次 //int i, n; double x, mypow=1; Scanner in=new Scanner(System.in);//从控制...

public static void main(String[] args){ System.out.println("输入n,按回车:"); Scanner s = new Scanner(System.in); Integer n = Integer.parseInt(s.next()); Integer re = factorial(1, n); System.out.println(re); } public static I...

实现思路:就是每次循环加1个数,循环的同时计算sum和这个数的和即可。 public static void main(String args[]){ int sum=0; int N =100;//自定义的N值,可以任意取 for (int i=1;i

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