www.fltk.net > 解方程:x/(x%2)+(x%9)/(x%7)=(x+1)/(x%1)+(x%8)/(...

解方程:x/(x%2)+(x%9)/(x%7)=(x+1)/(x%1)+(x%8)/(...

先是if(++x%2==0) 意思是 看i+1是否能被2整除 ,然后是if(++x%3==0) 是看i+2是否能被3整除,最后是if(++x%7==0) 是i+3是否能被7整除。输出的是i+3 而不是i 这个如果是个选择题 就把这几个选项带进去 首先这个输出的是偶数 逆着算 比较好算 填空...

解如图。

(x-6)/(x-7)+1/(7-x)=8 解:(x-6)/(x-7)-1/(x-7)=8 两边同时乘以x-7,得 x-6-1=8(x-7) x-7=8x-56 7x=56-7 7x=49 x=7 题目有问题?

解答如下:

解:去括号,得 3x-7x+7=3-2x-6 移项,得 3x-7x+2x=3-6-7 合并同类项,得 -2x=-10 系数化为1,得 x=5

1、解:2(x-3)+3(2x-1)=5(x+3) 2X-6+6X-3=5X-15 8X-9=5X-15 3X=-6 X=-2 2、解:7-x/4=x-3 7-X=4X-12 -5X=-19 X=19/5 3、解:4(x+5)=2-3(2x-7) 4X+20=2-6X+21 10X=3 X =3/10

(x-4)/(x-5) + (x-8)/(x-9) = (x-5)/(x-6) + (x-7)/(x-8) (x-5+1)/(x-5) + (x-9+1)/(x-9) = (x-6+1)/(x-6) + (x-8+1)/(x-8) 1+1/(x-5) + 1+1/(x-9) = 1+1/(x-6) + 1+1/(x-8) 1/(x-5) + 1/(x-9) = 1/(x-6) + 1/(x-8) 1/(x-9) - 1/(x-8) = 1/(x-6)...

x乘(x+1)乘(x+2)=504 x(x+1)(x+2)=504 x(x+1)(x+2)=7×8×9 x=7

(x-4)/(x-5)=(x-5+1)/(x-5)=1+(1/(x-5)) 原方程装换为 1+(1/(x-5))+1+(1/(x-9))=1+(1/(x-8))+1+(1/(x-6)) 1/(x-5)+1/(x-9)=1/(x-8)+1/(x-6) 设x-7=y 1/(y+2)+1/(y-2)=1/(y-1)+1/(y+1) 2y/(y*y-4)=2y/(y*y-1) y=0,x=7

1+1/7(x-1)=2+1/7{x-[1+1/7(x-1)]-2}, 两边乘以7,得到7+x-1=14+x-1-1/7(x-1)-2, 1/7(x-1)=5, x-1=35, x=36

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