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己知IA%6I+2BI%2I=0,求A%B的值

这题我会,先踩纳,我会把详细答案写下来发给你

|a+3|=0,a=-3,b=2

|a-3|>=0, |b+2|>=0 => a-3 = 0 b+2 = 0 => a = 3, b = -2 a的相反数-3,b的相反数2

因为平行成比例 i/1=1/2 的i=1/2

∵1?ia+bi=2+i,∴1-i=(a+bi)(2+i)=2a-b+(a+2b)i,则2a?b=1a+2b=?1,解得a=15b=?35,即复数a+bi在复平面内对应的点的坐标为(15,?35),位于第四象限,故选:D.

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|a-b+1|=a-b+1 |b-a-1|=a-b+1 故结果为:2(a-b+1)

∵b+ia+2i=(b+i)(a?2i)(a+2i)(a?2i)=ab+2+(a?2b)ia2+4=ab+2a2+4+a?2ba2+4i,又b+ia+2i=1+i,∴ab+2a2+4=1a?2ba2+4=1,解得:a=?1b=?3.∴a+b=-1-3=-4.故答案为:-4.

CIA={4},CIB={0,1},(CIA)∪(CIB)={0,1,4},故选C

ia1十1b1十丶丶丶 1m1=o 因为 |a|≥0,|b|≥0,|m|≥0 所以 |a|=0,|b|=0,|m|=0 从而 a=b=....=m=0

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