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化简y=sin2x/1%Cosx

(sin2x/sinx-cosx)-(sinx+cosx/tan2x-1) =[sin2x*(sinx+cosx)]/[(sinx-cosx)(sinx+cosx)]-(sinx+cosx)/[(sin2x/cos2x)-1] =[sin2x*(sinx+cosx)]/(sin2x-cos2x)-[cos2x(sinx+cosx)]/(sin2x-cos2x) =[(sinx+cosx)(sin2x-cos2x)]/(...

求y=cosx/cos2x的二阶导数 ,并求二阶导数的零点 解:dy/dx=(-cos2xsinx+2cosxsin2x)/cos²2x 令d²y/dx²=[cos²2x(2sin2xsinx-cos2xcosx-2sinxsin2x+4cosxcos2x)+4cos2xsin2x(-cos2xsinx+2cosxsin2x)]/cos⁴(2x)=0 约分...

>> clear >> x=-10:0.01:10; >> y=sin(2*x).*cos(x); >> plot(x,y,'color','r','linewidth',3); >> grid on

sin2x=2sinxcosx sin2xcosx=2sinx(cosx的平方)

(sin2x/sinx-cosx)-(sinx+cosx/tan2x-1) =[sin2x*(sinx+cosx)]/[(sinx-cosx)(sinx+cosx)]-(sinx+cosx)/[(sin2x/cos2x)-1] =[sin2x*(sinx+cosx)]/(sin2x-cos2x)-[cos2x(sinx+cosx)]/(sin2x-cos2x) =[(sinx+cosx)(sin2x-cos2x)]/(...

(sin2x/sinx-cosx)-(sinx+cosx/tan2x-1) =[sin2x*(sinx+cosx)]/[(sinx-cosx)(sinx+cosx)]-(sinx+cosx)/[(sin2x/cos2x)-1] =[sin2x*(sinx+cosx)]/(sin2x-cos2x)-[cos2x(sinx+cosx)]/(sin2x-cos2x) =[(sinx+cosx)(sin2x-cos2x)]/(...

y=2SinXcosX-2acosX-1=2cosX(SinX-a)-1,y=-(SinX-COSX)𠆢2-2aCosX!设y=y两式相等归元,。 2cosX(SinX-a)=-(sinX-CosX)𠆢2,1=2acosX,结果,cosX=1/2a,所以,1/a(sinX-a)=-(SinX-1/2a)𠆢2...

y=sin2x+cos2x y=√2 sin(2x+派/4)

(sin2x-cos2x+1)/(1+cotx) 分子 = sin2x -(1-2sin^2x)+1 = 2sin^2x + sin2x =2sinx(sinx+ cosx) 分母= (sinx+ cosx)/sinx 可以约分(sinx+ cosx) 所以原式2sin^2x

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