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(1)计算:2log 3 2%log 3 32 9 +log 3 8% ...

(1)2log 3 2-log 3 32 9 +log 3 8-25 log

-21.853209118683

2log3 2-log32/9+log3 8-5^log5 3 =2log3 2-log3 2+

最终答案:71/12

-1

1og₃32=5log₃2 log₃8

您好: log3(√27)+lg25+lg4+7^log7(1/2)+(-9.8)^0 =

用换底公式 原式=(lg3/lg4+lg3/lg8)(lg2/lg3+lg2/lg9) =(lg

(1)∵函数f(x)=log3(9x)?log3(3x),且19≤x≤9.∴f(3)=log3(9×

用换底公式 原式=(lg3/lg4+lg3/lg8)(lg2/lg3+lg2/lg9)-lg32/

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